Calorie data · Beverages← All foods

How many calories in
light beer?

Per 100g, light beer runs 29 calories and 1.6g of carbs. Macro-friendly enough for daily use.

29
kcal · 100g
0.2g
Protein
1.6g
Carbs
0g
Fat
Servings

Common serving sizes.

Calories scale with portion. Here's how a typical light beer serving translates in your tracker:

Serving
Calories
Protein
3 oz (85g)
25 kcal
0.2g
4 oz (113g)
33 kcal
0.2g
1 cup (~150g)
44 kcal
0.3g
In your day

What 29 calories means.

Very low calorie — at 29 kcal per 100g, light beer adds volume to a meal without meaningfully denting a calorie deficit.

Share of a 2,000-kcal day
1%
per 100g · 0.7g protein per 100 kcal
Time to burn it off
🚶 Walking6 min
🏃 Running3 min
🚴 Cycling3 min
Estimated for a 70 kg / 154 lb adult
Comparison

Light Beer vs. similar foods.

How light beer stacks up on calories and protein against foods people commonly compare it to:

Food
Calories
Protein / 100 kcal
Light Beer
29 kcal / 100g
0.7g
25 kcal / 100g
0g
35 kcal / 100g
0g
36 kcal / 100g
5.3g
Track this food

Skip the lookup. Snap the plate.

Point your iPhone camera at light beer and Spotwell's AI estimates the portion and macros in a few seconds. Check it, adjust anything that looks off, and log it.

Download on theApp Store
FAQ

Quick answers.

How many calories in light beer?

Light Beer has approximately 29 calories per 100g. A typical serving — 3 oz (85g) — comes in at 25 calories.

How much protein is in light beer?

0.2g of protein per 100g. That puts light beer at roughly 0.7g of protein per 100 calories — a useful lens when comparing to other beverages sources.

How do I log light beer accurately?

The simplest method: weigh it on a kitchen scale, then enter grams in your tracker. With Spotwell, you can skip the scale — point the camera at the plate and the AI estimates the portion in a few seconds. Adjust the value if it looks off.

Is light beer good for weight loss?

It depends on your overall calorie target. Light Beer is naturally low-calorie at 29 kcal per 100g, so it's easy to fit into a deficit.